The difference of square root of \(49\) and four squared is required.
The square root of \(49\) is \(9\) less than the value of \(4\) squared.
The square root of \(49\)
\(\sqrt{49}=7\)
The square of \(4\) is
\(4^2=4\times 4=16\)
The difference of the two numbers is
\(16-7=9\)
So, the square root of \(49\) is \(9\) less than the value of \(4\) squared.
Learn more:
https://brainly.com/question/14413003
https://brainly.com/question/21024310