bewellplus.gsu.edu
nickmitri nickmitri
  • 26-05-2014
  • Mathematics
Answered

How do you have factor y=6x²+24x-192 and find the zeros?

Verified Answer :

kate200468
kate200468 kate200468
  • 26-05-2014

\(y=6x^2+24x-192\\\\y=0\ \ \ \Leftrightarrow\ \ \ 6x^2+24x-192=0\ /:6\\\\x^2+4x-27=0\\\\x^2+2\cdot2\cdot x+2^2-2^2-27=0\\\\(x+2)^2-31=0\\\\(x+2)^2=31\ \ \ \Leftrightarrow\ \ \ (x+2= \sqrt{31} \ \ \ or\ \ \ x+2=- \sqrt{31})\\\\x=-2+ \sqrt{31}\ \ \ or\ \ \ x=-2- \sqrt{31}\)

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