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sydneyrae97 sydneyrae97
  • 09-09-2015
  • Mathematics
Answered

how do i solve


8x^(2/3)-39x^(1/3)-5=0

Verified Answer :

ayah1
ayah1 ayah1
  • 09-09-2015

\(8 x^{ \frac{2}{3} } -39 x^{ \frac{1}{3} } -5=0\)

\(8 \sqrt[3]{ x^{2} } -39 \sqrt[3]{ x^{1} } - 5=0\)

\(8 \sqrt[3]{ x^{2} } -39 \sqrt[3]{ x } = 5\)

\(8( \sqrt[3]{ x^{2} } )^{3} -39( \sqrt[3]{ x })^{3} =5 ^{3}\)

\(8 x^{2} -39x =5 ^{3}\)

\(8 x^{2} -39x =125\)

\(8 x^{2} -39x - 125 = 0\)

Hope this helps '-'

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