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Ttime69 Ttime69
  • 18-05-2014
  • Mathematics
Answered

Verify

(2cos2x)/(sin2x) - cotx - tanx = -2tanx

Verified Answer :

Ryan2
Ryan2 Ryan2
  • 18-05-2014

Remember:

\(\boxed{sin(2x)=2.sinx.cosx}\\ \\ and\\ \\ \boxed{cos(2x)=cos^2x-sin^2x}\)


\(\frac{2cos2x}{sin2x}-cotx-tanx=\\ \\ \frac{2(cos^2x-sin^2x)}{2sinx.cosx}-\frac{cosx}{sinx}-\frac{sinx}{cosx}=\\ \\ \frac{cos^2x-sin^2x}{sinx.cosx}-\frac{cosx}{sinx}-\frac{sinx}{cosx}=\\ \\ \frac{cos^2x-sin^2x-cos^2x-sin^2x}{sinx.cosx}=\\ \\ \frac{-2sin^2x}{sinx.cosx}=\\ \\ \frac{-2sinx}{cosx}=-2.tanx\)

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