Verified Answer :

naǫ

\(x+y=12 \\ x-2y=6 \ \ \ \ \ \ \ \ \ |\times (-1) \\ \\ x+y=12 \\ \underline{-x+2y=-6} \\ y+2y=12-6 \\ 3y=6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\div 3 \\ y=2 \\ \\ x+y=12 \\ x+2=12 \ \ \ \ \ \ \ \ \ \ |-2 \\ x=10 \\ \\ \boxed{x=10, \ y=2}\)

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