\(\frac{4x^2+8x}{x^2-x-6}\\\\Domain:x^2-x-6
eq0\\\\x^2-3x+2x-3\cdot2=x(x-3)+2(x-3)=(x-3)(x+2)\\\\x^2-x-6
eq0\iff(x-3)(x+2)
eq0\iff x-3
eq0\ or\ x+2
eq0\\\\therefore\ x
eq3\ and\ x
eq-2\\------------------\\the\ nominator:\ 4x^2+8x=4x\cdot x+4x\cdot2=4x(x+2)\\the\ denominator:x^2-x-6=(x-3)(x+2)\)
\(therefore\ simplify\ form:\\\\\frac{4x^2+8x}{x^2-x-6}=\frac{4x(x+2)}{(x-3)(x+2)}=\boxed{\frac{4x}{x-3}}\)