With an expression like this, you have to raise all the terms to the 3rd power. So the 5 will become \(5^{3}=125\), \(x^{2}\) will become \((x^{2} )^3= x^{6}\), the 4 will become \(4^{3}=64\) and finally, the \(y^{4}\) becomes \((y^{4})^3=y^{12}\). If you place all of these together in the same fraction, the new answer equivalent to the initial expression is \(\frac{125x^{6}}{64y^{12}}\)
