what are the roots of the equation x^2+4x-16=0
OK so you need to use the quadratic formula with a=1, b=4, c=-16. −b±√b^2−4ac x= ------------------ 2a −(4)±√(4)^2−4(1)(−16) x= ----------------------------- 2(1) −4±√80 x= --------------- 2 Your final answer is: x=−2+2√5 or x=−2−2√5
x² + 4x - 16 = 0x = -(4) ± √((4)² - 4(1)(-16)) 2(1)x = -4 ± √(16 + 64) 2x = -4 ± √(80) 2x = -4 ± 4√(5) 2x = -2 ± 2√(5)x = -2 + 2√(5) U x = -2 - 2√(5)