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Which statement about 6x2 + 7x – 10 is true? One of the factors is (x + 2). One of the factors is (3x – 2). One of the factors is (2x + 5). One of the factors is (x – 5).

Verified Answer :

naǫ

\(6x^2+7x-10=\\ 6x^2+12x-5x-10= \\ 6x(x+2)-5(x+2)= \\ (6x-5)(x+2)\)

The true statement is: one of the factors is (x+2).

calculista

we have that

\(6x^{2} +7x-10\)

Find the factors


\(6x^{2} +7x-10 \\ 6 x^{2} +12x-5x-10=0 \\ 6x(x+2)-5(x+2)=0 \\ (6x+5)*(x+2)=0\)

therefore

the factors are
\((6x-5) and (x+2)\)

the answer is

One of the factors is \((x+2)\)

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