square root of 64 over 25
so \(\sqrt{\frac{64}{25} }\)that is equal to \(\frac{ \sqrt{64}}{ \sqrt{25}} = \frac{8}{5}\)
Refresh page if you see [ tex ]Knowing that \(64 = 8^2\quad\text{and}\quad25 = 5^2\), we have\(\sqrt{\dfrac{64}{25}} = \dfrac{\sqrt{64}}{\sqrt{25}} = \boxed{\dfrac{8}{5}}\)
