bewellplus.gsu.edu
selenasarahi selenasarahi
  • 18-05-2015
  • Mathematics
Answered

The length of a rectangle is six times its width.

If the area of the rectangle is 600yd^2, find its perimeter.

Verified Answer :

darth666
darth666 darth666
  • 18-05-2015

rectangle area = ab
perimeter = 2(a+b)

a - lenght
b - width

a = 6b

ab=600
6bb=600
\(6b^2=600\)
\(b^2=100\)
\(b=\sqrt{100}\)
b=10
a = 610 = 60
Perimeter = 2(a+b)=2(60+10)=2*70=140 yd


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