In a certain lottery, the winner of the first ticket drawn receives $10. Each succeeding ticket drawn is worth $15 more than the previous ticket. How much does the holder of the tenth ticket drawn receive?
The value of each winning ticket is an arithmetic series in which T (n) = -5 + 15n or $5 (3n-1). The first winner is 5 (3x1 - 1) = $10. The second winner is 5 (3x2 - 1) = $25. The tenth ticket wins $5 (3x10 - 1) = $5 (29) = $145.
