tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)(tan x) ] => (tan 3x)[ 1 - (tan 2x)(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.
