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abboobrouillet
abboobrouillet abboobrouillet
  • 06-05-2015
  • Mathematics
Answered

how do you solve


\(x^{2} -8x=65\)


is it \((x-4)^2-81\)

Verified Answer :

Panoyin
Panoyin Panoyin
  • 25-06-2015

x² - 8x = 65
                      x² - 8x + 16 = 65
               x² - 8x + 16 - 65 = 65 - 65
        x² - 4x - 4x + 16 - 65 = 0
x(x) - x(4) - 4(x) + 4(4) - 65 = 0
        x(x - 4) - 4(x - 4) - 65 = 0
               (x - 4)(x - 4) - 65 = 0
                       (x - 4)² - 65 = 0

It is actually (x - 4)² - 65.

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