Let's set up some equations.
Our first number is going to be \(a\) and the other will be \(b\).
\(4\times a=b\)
\(b-a=24\)
We can substitute \(b\) for \(4\times a\) in the second equation to end up with
\(4\times a-a=24\)
\(4a\) minus \(a\) is going to be \(3a\).
\(3a=24\)
\(\boxed{a=8}\)
And since \(a=8\), \(b=4\times a=4\times 8=\boxed{32}\)
