If 4^x+1 = 64, then what is the value of x^4
\(4^{x} + 1 = 64 \\4^{x} = 63 \\ln(4^{x}) = ln(63) \\xln(4) = ln(63) \\x = \frac{ln(63)}{ln(4)}\)\((\frac{ln(63)}{ln(4)})^{4} = 79.78006702\)The value of x⁴ is equal to 79.8006702
