An aircraft on it's take-off run has a steady acceleration of 3m/s^2. How much velocity does it gain 10 seconds?
Acceleration measures how fast the speed changes over time.
So, over 10s, the aircraft's speed changes by 3\(\frac{m}{ s^{2} }\) * 10s
So, the change is 30\(\frac{m}{s}\)
Note that the one of the second units cancels out in the answer.
To solve this, let's use the formula a=(v''-v')÷(t)
3=(v''-0)÷(10)
3=v÷10
Now isolate for velocity
v"=(3)(10)
v"=30 m/s!