Find the number of solutions :4x-2y=8y=2x+8
I think it would be no solution4x-2(2x+8)=84x-4x+16=80x+16=816=8which is wrong
\(\begin{cases} 4x-2y=8 \\ y=2x+8 \end{cases} \\ \\\begin{cases} 4x-2y=8 \\-2x+ y= 8 \ \ /*2\end{cases}\\ \\\begin{cases} 4x-2y=8 \\-4x+ 2y= 16 \ \ /*2\end{cases} \\+ \ \ -------- \\ 0=24 \\ \\ Answer : \ no \ solution\)
