bewellplus.gsu.edu
samrockz samrockz
  • 17-04-2015
  • Mathematics
Answered

Solve this equation by factoring

6n^2-18n-18=6

Verified Answer :

konrad509
konrad509 konrad509
  • 17-04-2015

\(6n^2-18n-18=6 \\ 6n^2-18n-24=0\\ n^2-3n-4=0\\ n^2+n-4n-4=0\\ n(n+1)-4(n+1)=0\\ (n-4)(n+1)=0\\ n=4 \vee n=-1\)

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dln
dln dln
  • 17-04-2015

\(6n^{2}-18n-18=6 \\ 6n^{2}-18n-24=0 \\ 6(n^{2}-3n-4)=0 \\ 6(n-4)(n+1)=0 \\ \boxed{n=4\ and\ -1}\)

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