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Verified Answer :

\(9x^2=1\\ x^2=\dfrac{1}{9}\\ x=-\dfrac{1}{3} \vee x=\dfrac{1}{3}\)

\(9x^2 = 1 \\ \frac{9x^2}{9} = \frac{1}{9}\)

\(x^2 = \frac{1}{9} \\ \sqrt{ \frac{1}{9} } = 1/3\), \(- 1/3\)