\(2x^2 = 27 + 3x \\ \\2x2 -3x-27=0 \\ \\ a=2 , \ b = -3 , \ c=-27 \\ \\\Delta = b^{2}-4ac = (-3)^{2}-4*2*(-27)= 9+216 =225\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{3-\sqrt{225}}{2*2}=\frac{3-15}{4} =\frac{-12}{4}= -3\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} = \frac{3+\sqrt{225}}{2*2}=\frac{3+15}{4} =\frac{18}{4}= \frac{9}{2}=4.5\)
