how do i solve 2x^2+5x+2=9
2x² + 5x + 2 = 92x² + 5x + 2 - 9 = 9 - 92x² + 5x - 7 = 0x = -5 +/- √(5² - 4(2)(-7)) 2(2)x = -5 +/- √(25 + 56) 4x = -5 +/- √(81) 4x = -5 +/- 9 4x = -5 + 9 x = -5 - 9 4 4x = 4 x = -14 4 4x = 1 x = -3.5
\(2x^2+5x+2=9\\ 2x^2+5x-7=0\\ 2x^2-2x+7x-7=0\\ 2x(x-1)+7(x-1)=0\\ (2x+7)(x-1)=0\\ x=-\dfrac{7}{2} \vee x=1\)