Solve the equation for a. D=vt+1/2at^2
D = vt + 1/2at^2D - vt = 1/2at^22(D - vt)/t^2 = a
\(D=vt+\frac{1}{2}at^2\\\\\frac{1}{2}at^2+vt=D\ \ \ \ /-vt\\\\\frac{1}{2}at^2=D-vt\ \ \ \ /\cdot2\\\\at^2=2D-2vt\ \ \ \ /:t^2\\\\a=\frac{2D-2vt}{t^2}\)