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Lightfoote31
Lightfoote31 Lightfoote31
  • 25-03-2015
  • Mathematics
Answered

What is the inverse function of g(x)=1/x-2

Verified Answer :

konrad509
konrad509 konrad509
  • 25-03-2015

Assuming it's \(g(x)=\dfrac{1}{x-2}\)

\(y=\dfrac{1}{x-2}\\ x-2=\dfrac{1}{y}\\ x=\dfrac{1}{y}+2\\ g^{-1}(x)=\dfrac{1}{x}+2\)

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