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MckinleyMcgurl MckinleyMcgurl
  • 17-03-2015
  • Chemistry
Answered

For the reaction 2Na(s) + Cl2(g) --> 2NaCl(s), how many grams of NaCl could be produced from 20 L of Cl2 (at STP)?

Verified Answer :

theresaleigh theresaleigh
  • 18-03-2015

13.0 L Cl2 × 1 mol Cl2
/22.4 L Cl2
= 0.580 mol Cl2
103.0 g Na × 1 mol Na/23 g Na = 4.48 mol Na
Cl 2
is limiting reagent: 0.580 mol Cl2 × 2 mol NaCl/1 mol Cl2
= 1.16 mol NaCl
1.16 mol NaCl × 58 g NaCl/1 mol NaCl = 67.3 g NaCl
DIF: L3 REF: p. 371 OBJ: 12.3.1

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