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mandaa97 mandaa97
  • 13-03-2015
  • Mathematics
Answered

(x-4)^2+(y+12^2)=17^2 what is the length of its radius

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Since3122015
Since3122015 Since3122015
  • 13-03-2015

\((x-4)^{2} + (y+12)^{2} = 17^{2} \\ x^{2} + y^{2} = r^{2} \\ r^{2} = 17^{2} \\ \sqrt{ r^{2} } = \sqrt{ 17^{2} } \\ r=17\)

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konrad509
konrad509 konrad509
  • 13-03-2015

\(\text{The standard form equation of a circle is }(x-x_1)^2+(y-y_1)^2=r^2\\\\ (x-4)^2+(y+12)^2=17^2 \\ \Downarrow\\ r^2=17^2\\ r=17\)

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