\(different\ between\ \frac{5}{8}\ and\ \frac{1}{2}=\frac{5}{8}-\frac{1}{2}=\frac{5}{8}-\frac{4}{8}=\frac{1}{8}\\\\different\ between\ 1\ and\ \frac{5}{8}=1-\frac{5}{8}=\frac{8}{8}-\frac{5}{8}=\frac{3}{8}\\\\\frac{1}{8} \ \textless \ \frac{3}{8}\ therefore\ \frac{5}{8}\ is\ closest\ to\ \frac{1}{2}\)