\(n-2\frac{ 1}{4}=1 \frac{1}{6} | +2\frac{1}{4}\\ \
-2\frac{ 1}{4} +2\frac{1}{4}=1 \frac{1} {6}+2\frac{1}{4} \\ \
=1 \frac{1} {6}+2\frac{1}{4} \\ \\the \ common \ denominator \ is \ 12 \\ \
=1 \frac{2} {12}+2\frac{3}{12} =3\frac{2+3}{12}=3\frac{5}{12}\)
