what is the zero for 2x2-7=4
2x^2-7=4subtract 4 from both sdies2x^2-11=0therefor2x^2=11divide by 2x^2=5.5square root both sdiesx=-2.345 or 2.345
2x² - 7 = 4 +7 +7 2x² = 11 2 2 x² = 5 1/2 x = √5 1/2
