Answer:
20 sq.units
Step-by-step explanation:
Given: The base of a parallelogram is 8 units, and the height is 5 units. A segment divides the parallelogram into two identical trapezoids. The height of each trapezoid is 5 units
To Find: Area of one of the trapezoid.
Solution: Consider the file attached with solution.
In Parallelogram ABCD,
\(\text{CD}\)=\(8\text{unit}\)
\(\text{height}=5\text{unit}\)
therefore,
area of parallelogram \(area(\text{ABCD})=\text{base}\times\text{height}\)
\(8\times5\)
\(area(\text{ABCD})\)=\(40\text{unit}\)
Segment EF divides parallelogram in two identical trapezoid AEFD and CFEB
therefore,
\(area(\text{AEFD})=area(\text{CFEB})\)
also,
\(area(\text{AEFD})+area(\text{CFEB})=area(\text{ABCD})\)
now area of one of the trapezoid \(\text{AEFD}\)
\(2\times area(\text{AEFD})=area(\text{ABCD})\)
\(area(\text{AEFD})=\frac{area(\text{ABCD})}{2}\)
\(area(\text{AEFD})=\frac{40}{2}=20\)
The area of trapezoid is \(20\text{sq.units}\)
