What is the voltage of a battery that powers a light with .43 a and has a resistance of 3.5 ohms?
Answer:
The voltage of the battery is \(1.505V\)
Explanation:
To answer this question we are going to use the Ohm Law.
Ohm Law is a law that states that the voltage across a resistor is directly proportional to the current flowing through the resistance multiply by the value of the resistance.
Mathematically, we can write :
\(V=I.R\) (I)
Where V is the voltage
Where I is the current
And where R is the resistance
The unit of voltage is V which is volt
The unit of current is ''a'' which is ampere
And the unit of resistance is ohm
If we replace all the data in equation (I) :
\(V=I.R\)
\(V=(0.43a).(3.5ohm)=1.505V\)
The voltage of the battery is \(1.505V\)