The molarity of 32.1 g of MgS in 841 mL of solution is 0.678M
CALCULATE MOLARITY:
- The molarity of a solution can be calculated by dividing the number of moles by volume. That is;
Molarity (M) = no. of moles (n) ÷ volume (V)
- In this question, 32.1g of MgS is given. We must first calculate the number of moles of MgS present in that mass by using the formula as follows:
moles = mass ÷ molar mass
Molar mass of MgS = 24 + 32 = 56g/mol
moles = 32.1g ÷ 56g/mol
moles = 0.57mol
- Therefore, the molarity of the MgS solution can be calculated as follows:
Volume = 841mL = 0.841L
Molarity = 0.57mol ÷ 0.841L
Molarity = 0.678M
- Therefore, the molarity of 32.1 g of MgS in 841 mL of solution is 0.678M.
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