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nightmist

Mr of C6H12O6= (126)+(121)+(166)=180 
Mr of O2=(162)=32 

If 180 g of glucose requires 632 g of oxygen 
38 g of glucose would need 632/180 38=40.53 g of oxygen 
ans=40.53 

mr of CO2=44 
If 180 g of glucose gives 446 g of CO2 
therefore 38 g of it gives 446/180 38 = 55.73 g of CO2

yassirmomand

i think that it equal to co=3 h=2 o=1


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