a. Inversely proportional is an equation with two variables a and b such that when the value of a increases value of b decreases and vise versa. The inverse equation for the given question is \(c=\dfrac{k}{d}\)
b. The value of the d is 2312 units when c is 68 units.
Given-
c and d vary inversely where d is 2 units and c is 17 units.
\(c\propto \dfrac{1}{d}\)
Part A
Equation that models the variation:
To convert this proportion into an equation, multiply by a constant k and find the value of constant.
\(c=\dfrac{k}{d}\)
This is the required equation, now solving further for the value of constant k,
\(c\times d=k\)
\(k=c\times d\)
\(k=17\times 2\)
\(k=34\)
Part B
Value of d when the value of c is 68 units.
By the inverse equation,
\(c=\dfrac{k}{d}\)
\(68=\dfrac{34}{d}\)
\(d=68\times 34\)
\(d=2312\)
Hence, the value of the d is 2312 units when c is 68 units.
For more about inverse follow the link given below,
https://brainly.com/question/13715269
