find the 25th term, given the first term and the common difference.
a=5 and d=5 i will mark the brainlist
1
\(\bf \textit{the }n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad
\begin{cases}
a_1=\textit{first term in the sequence}\\
d=\textit{common difference}
\end{cases}
\\\\\\
a_{25}=a_1+(25-1)d\impliedby 25^{th}\ term\)
plug in the provided values then
Answer: The required 25-th term of the given sequence is 125.
Step-by-step explanation: We are given to find the 25-th term of a sequence with first term and common difference as follows :
a = 5 and d = 5.
Since we are dealing with common difference, so the given sequence must be an arithmetic one.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is given by
\(a_n=a+(n-1)d.\)
Therefore, the 25-th term of the given arithmetic sequence will be
\(a_{25}=a+(25-1)d=5+24\times5=5+120=125.\)
Thus, the required 25-th term of the given sequence is 125.