Answer: C) 32 five-dollar bills
Step-by-step explanation:
Let x be the number of $10 bills and y be the number of $5 bills .
Then according to the given question we have,
\(x+y=38...............(1)\\\\10x+5y=220\)
Multiplying equation (1) by 10 on both sides, we get
\(10x+10y=380..............................(3)\)
Now, subtract equation (2) from (3), we get
\(5y=160\\\\\Rightarrow\ y=32\)
Hence, there were 32 five dollars bills in deposit.
