Can someone help me on #6
one of the ways you could do it would be 10d + 2d you just add both 5d's and both d's because they are common factors.
A rectangle is 5 times as long as its width, meaning that length/5 = widthSo the perimeter could also be stated as:l + l + \(\frac{1}{5}\)l + \(\frac{1}{5}\)l