when 7/8x^2-3/4 x is subtracted from 5/8x^2-1/4x+2 the difference is?
Answer:
\(-\frac{1}{4}x^{2}+\frac{1}{2}x+2\)
Step-by-step explanation:
In this problem we have
\((\frac{5}{8}x^{2} -\frac{1}{4}x+2)- (\frac{7}{8}x^{2} -\frac{3}{4}x)\)
Group terms that contain the same variable
\((\frac{5}{8}x^{2} -\frac{1}{4}x+2)- (\frac{7}{8}x^{2} -\frac{3}{4}x)=(\frac{5}{8}x^{2}-\frac{7}{8}x^{2})+(-\frac{1}{4}x+\frac{3}{4}x)+(2)\)
\(=(-\frac{2}{8}x^{2})+(\frac{2}{4}x)+(2)\)
Simplify
\(=-\frac{1}{4}x^{2}+\frac{1}{2}x+2\)