The population of a type of local bass can be found using an infinite geometric series where a1 = 94 and the common ratio is one third. Find the sum of this infinite series that will be the upper limit of this population.
Answer:
The sum of this infinite series that will be the upper limit of this population is, 141
Step-by-step explanation:
Formula for infinite geometric series is given by:
\(S = \frac{a_1}{1-r}\) ....[1]
where,
\(a_1\) is the first term,
r is the common ratio term.
As per the statement:
The population of a type of local bass can be found using an infinite geometric series where:
\(a_1 = 94\)
\(r = \frac{1}{3}\)
To find the sum of this infinite series that will be the upper limit of this population.
Substitute the given values in [1] we have;
\(S = \frac{94}{1-\frac{1}{3}} = \frac{94}{\frac{2}{3}} = 94 \cdot \frac{3}{2} = 47 \cdot 3 = 141\)
Therefore, 141 is the sum of this infinite series that will be the upper limit of this population.