Factor completely 18b - 32
Factor 18b−3218b−32=2(9b−16)Answer:2(9b−16)
Answer:
\(2(9b-16)\)
Step-by-step explanation:
we have
\(18b-32\)
we know that
\(18=2*3^{2}\)
\(32=2^{5}\)
substitute
\(18b-32=2*3^{2}b-2^{5}\)
Factor \(2\)
\(=2(3^{2}b-2^{4})\)
\(=2(9b-16)\)
