Answer:
The value of f(3) is 0.148(approx)
Step-by-step explanation:
Given the function: \(f(x) = 4(\frac{1}{3})^x\) ......[1]
we have to find the value of f(3).
substitute the value of x =3 in [1]
use: \((\frac{a}{b})^n = \frac{a^n}{b^n}\)
then, we have;
\(f(3) = 4(\frac{1}{3})^3 = \frac{4}{3^3} =\frac{4}{27} = 0.1481481....\)
therefore, the value of f(3) is 0.148(approx)
