Joanna has nickels, dimes, and pennies in a jar. The probability of drawing a nickel from the jar is 0.3, the probability of drawing a dime is 0.2, and the probability of drawing a penny is 0.5. Joanna picks a coin from the jar 240 times, replacing each coin before the next draw. About how many times would Joanna pick a dime in 240 draws?
Answer:
The required number of times Joanna would pick a dime in 240 draws = 48
Step-by-step explanation:
The probability of drawing a nickel from the jar is 0.3
The probability of drawing a dime is 0.2
The probability of drawing a penny is 0.5
Also, The total number of times a coin is picked from the jar = 240
Now, we need to find the total number of times Joanna would pick a dime
⇒ The required number of times Joanna would pick a dime = Probability of picking up a dime × Total number of draws
⇒ The required number of times Joanna would pick a dime = 0.2 × 240
⇒ The required number of times Joanna would pick a dime = 48
Therefore, The required number of times Joanna would pick a dime in 240 draws = 48