Answer:
Area of a square(A) is given by:
\(A = s^2\), where s is the side of the square.
Area of a triangle(A') is given by:
\(A' = \frac{1}{2} \cdot b \cdot h\)
From the given figure:
Labelled the diagram shown below.
In a triangle ABC:
BC = 5 cm and FA =4 cm
then;
\(\text{A'} = \frac{1}{2} \cdot \text{BC} \cdot \text{FA}\)
Substitute the given values we have;
\(A' = \frac{1}{2} \cdot 5 \cdot 4 =5 \cdot 2= 10 cm^2\)
Now, find the area of square BCDE:
Side of the square BCDE (s)= 5 cm
then;
\(A = (5)^2 = 25 cm^2\)
Then the area of the given composite figure :
\(A+A' = 25+10 = 35 cm^2\)
Therefore, the area of the given figure is, \(35 cm^2\)
