The side length, s, of a cube is 3x + 2y. If V = s3, what is the volume of the cube?
V = (3x + 2y)³ = (3x + 2y)(3x + 2y)(3x + 2y)
V = (9x² + 12xy + 4y²)(3x + 2y)
V = 27x³ + 36x²y + 12y²x +18x²y + 24xy² + 8y³
V = 27x³ + 54x²y + 36y²x + 8y³
Answer:
\(27x^3+8y^3+54x^2y+36xy^2\)
Explanation:
We have given with a cube whose side is \(3x+2y\) and we need to find the volume of a cube
Whose volume is defined by \(v=s^3\)
So, according to the formula we will get
\((3x+2y)^3\)
Using the fomula
\((a+b)^3=a^3+b^3+3a^2b+3ab^2\)
Here a=3x and b=2y substituting in the formula we will get
\((3x+2y)^3=(3x)^3+(2y)^3+3(3x)^2(2y)+3(3x)(2y)^2\)
After simplification we will get
\(27x^3+8y^3+54x^2y+36xy^2\)
Hence, volume of cube is \(27x^3+8y^3+54x^2y+36xy^2\)