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Verified Answer :

Simplified form would be twentieth root of 6

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Answer:

\(\sqrt[20]{6}\)

Step-by-step explanation:

we need to simplify

\(\frac{\sqrt[4]{5}}{\sqrt[5]{6}}\)

Each radical can be written in fraction form

\(\sqrt[4]{6} = 6^{\frac{1}{4}}\)

\(\sqrt[5]{6} = 6^{\frac{1}{5}}\)

\(\frac{\sqrt[4]{5}}{\sqrt[5]{6}}=\frac{6^{\frac{1}{4}}}{6^{\frac{1}{5}}}\)

Both top and bottom have same base so we subtract the exponents

\(6^{\frac{1}{4} -\frac{1}{5}}\)

Take common denominator to subtract the fractions

\(\frac{1*5}{4*5} -\frac{1*4}{5*4}\)

\(\frac{5-4}{20} =\frac{1}{20}\)

\(6^{\frac{1}{4} -\frac{1}{5}}=6^\frac{1}{20}\)

\(6^\frac{1}{20} =\sqrt[20]{6}\)