Answer:
(1,3) and (2,4).
Step-by-step explanation:
The inequality is \(y > -x^2+5\), so
for (0,5):
\(5> -(0)^2+5\)
\(5> 0+5\)
\(5>5\), that is false, then (0,5) is not in the solution set of \(y > -x^2+5\).
for (1,3):
\(3> -(1)^2+5\)
\(3> -1+5\)
\(3>4\), that is false, then (1,3) is not in the solution set of \(y > -x^2+5\).
for (2,4):
\(4> -(2)^2+5\)
\(4> -4+5\)
\(4>1\), that is true, then (2,4) is in the solution set of \(y > -x^2+5\).
