What are the solutions of the quadratic equation below?
-7x2 - 23x + 10 = 0
The solutions to the given quadratic equation are x = -3.67 and x = 0.39
From the question, we are to determine the solutions of the given quadratic equation
The given equation is
-7x² - 23x + 10 = 0
Using the formula method,
\(x = \frac{-b \pm\sqrt{b^{2} -4ac} }{2a}\)
a = -7, b = -23, and c = 10
\(x = \frac{-(-23) \pm\sqrt{(-23)^{2} -4(-7)(10)} }{2(-7)}\)
\(x = \frac{23 \pm\sqrt{529 +280} }{-14}\)
\(x = \frac{23 \pm\sqrt{809} }{-14}\)
\(x = \frac{23 \pm28.44 }{-14}\)
\(x = \frac{23 +28.44 }{-14}\) OR \(x = \frac{23 -28.44 }{-14}\)
\(x = \frac{51.44 }{-14}\) OR \(x = \frac{-5.44 }{-14}\)
x = -3.67 OR x = 0.39
Hence, the solutions to the given quadratic equation are x = -3.67 and x = 0.39
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