This how do I get the awnser
3)m<1 = 59m<2 = 90 - 59 = 31m<3 = 59m<4 = m<2 = 31m<5 = m<2 = 31m<6 = m<1 = 59m<7 = 180 - (31 +31) = 180 - 62 = 118m<8 = 180 - 118 = 624)m<BCD = 90m<ABD = m<BDC = 16m<CBE =90 - 16 = 74m<ADE = m<CBE = 74m<AEB = m<DEC = 180 - (16+16) = 180 - 32 = 148m<DEA = 180 - 118 = 32