Data:
\(A_{base} = 4 \frac{3}{4} = \frac{4*4+3}{4} = \frac{16+3}{4} \to A_{base} = \frac{19}{4}\)
\(h (height) = 2 \frac{1}{3} = \frac{3*2+1}{3} = \frac{6+1}{3} \to h (height) = \frac{7}{3}\)
\(v (volume) = ?\)
Formula: \(V = A_{b}*h\)
Solving:
\(V = A_{b}*h\)
\(V = \frac{19}{4} * \frac{7}{3}\)
\(V = \frac{133}{12}\)
\(V = 11.08333....\)
\(\boxed{\boxed{V \approx 11.08}}\end{array}}\qquad\quad\checkmark\)
