Note¹: One integer is 6/6 of the wall
Note²: Make the rule of three simple
ton __ Coverage
\(\frac{2}{5}\) --------------- \(\frac{5}{6}\)
y --------------- \(\frac{6}{6}\)
Solving: (directly proportional)
\(\frac{ \frac{2}{5} }{y}= \frac{ \frac{5}{6} }{ \frac{6}{6} }\)
Product of extremes equals product of means
\(\frac{5}{6} *y = \frac{2}{5} * \frac{6}{6}\)
\(\frac{5y}{6} = \frac{12}{30}\)
Product of extremes equals product of means
\(5y*30 = 6*12\)
\(150y = 72\)
\(y = \frac{72}{150} \frac{\div6}{\div6} \to \boxed{\boxed{y = \frac{12}{25} }}\end{array}}\qquad\quad\checkmark\)
Answer:
\(\frac{12}{25}\:\textbf{ton\:of\:concrete}\) or 0.48 ton of concrete
